Given one mole of each substance, which of the following will produce the FEWEST particles in aqueous solution? 1. sodium nitrate 2. CH2Cl2 3. sodium phosphate 4. K2SO4

CH2Cl2 produces the fewest particles

Explanation:

Step 1: Data given

1. sodium nitrate = NaNO3

2. CH2Cl2

3. sodium phosphate = Na3PO4

4. K2SO4

Step 2

NaNO3 → Na+ +NO3-

1. Sodium nitrate (NaNO3) dissociates into one Na^+ ion and one nitrate (NO3^-) ion. In total we have 2 particles.

2. CH2Cl2 is a covalent compound, so, it doesn't dissociate. So, one particle.

3) Na3PO4 → 3Na+ + PO4^3-

Sodium phosphate (Na3PO4) is  an ionic compound. It dissociates into 3 Na^+ ions and 1 phosphate(PO4^-3) ion. In total, 4 particles.

4) K2SO4 → 2K+ + SO4^2-

Because K2SO4 is an "ionic" compound, it dissociates into 2 K^+ ions, and one sulfate(SO4^-2) ion. So, 3 particles.

CH2Cl2 produces only 1 particle so it has the fewest particles

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