Chemistry, 07.03.2020 03:26 danielahchf

Given that a commercial airliner has a range a range of 9,500 miles using 265 tons of JP-4 fuel. Estimate the range of the aircraft burning either gaseous or liquid hydrogen at.

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Answer from: cailynrachael

Here is the full question.

Given that a commercial airliner has a range of 9,500 miles using 265 tonnes of JP-4 fuel. Estimate the range of the aircraft burning either gaseous or liquid hydrogen at the same mass of hydrogen as JP4.

The dry mass of the aircraft is 800 tonnes. The fuel properties are as follows:

Fuel Density (kg/m³) Heating value (kJ/kg)

JP4 800.0 45000

H₂ (gaseous, S.T.P) 0.0824 120900

H₂ (liquid, 1 atm) 70.8 120900

25,514 mi

Explanation:

Let first calculate the value of initial mass of the aircraft m_1 when burning JP4 fuel by using the expression:

$m_1 =m_2 + m_{JP4}$

where;

m_2 = 800t

$m_{JP4} = 265t$

m_1 = 800t+265t

m_1=1065 t

We need to employ the use of the range of the airliner which can be expressed by the formula;

$s = \eta__0}(\frac{L}{\delta g})In(\frac{m_1}{m_2})(\frac{Q_R}{g})$

where;

$\eta__0}$ = overall efficiency

L = lift

$\delta g$ = drag force

m_1 = initial mass of the vehicle

m_2 = is the final mass of the airliner after the burning of fuel

Q_R = is the heat of the reaction of the fuel burning.

g = gravitational acceleration

Rearranging the above equation; we have:

$\eta__0}(\frac{L}{\delta g}) = \frac{ s}{In(\frac{m_1}{m_2})({Q_R})}$

$\eta__0}(\frac{L}{\delta g}) = \frac{9500 mi}{In(\frac{1065t}{800t})({45000 kJ/kg})}$

$\eta__0}(\frac{L}{\delta g}) = \frac{0.2111}{In(1.33)}$

$\eta__0}(\frac{L}{\delta g}) = 0.74 mi.kg/kJ$

To estimate the range of the aircraft burning either gaseous or liquid hydrogen at the same mass of hydrogen as JP4; we have:

$s = \eta__0}(\frac{L}{\delta g})In(\frac{m_1}{m_2})(\frac{Q_R}{g})$

$s= (0.74mi.kg/kJ)(120900kJ/kg)In(\frac{1065t}{800t})$

$s= (89466mi)In(\frac{1065t}{800t})$

s = (89466mi)In(1.33)

s = 25,513.82 mi

s ≅ 25,514 mi

Thus, the range of the aircraft when burning either gaseous or liquid hydrogen at the same mass of hydrogen as JP4 is 25,514 mi

Answer from: Quest

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

Answer from: Quest

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.

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Given that a commercial airliner has a range a range of 9,500 miles using 265 tons of JP-4 fuel. Est...

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