In the following acid-base reactions, identify the spectator ions, if any:
(i) Cesium hydroxide(aq) + nitric acid(aq) =>
(ii) Calcium hydroxide(aq) + acetic acid(aq) =>
a.
(i) Cs+ and NO3-
(ii) no spectator ions
b.
(i) Cs+ and NO3-
(ii) H+ and OH-
c.
(i) no spectator ions
(ii) H+ and OH-
d.
(i) Cs+ and NO3-
(ii) Ca2+ and acetate ion.
e.
(i) no spectator ions
(ii) no spectator ions

Answer : The correct option is, (d)

(i)

(ii)

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(i) The balanced molecular equation will be,

The complete ionic equation in separated aqueous solution will be,

In this equation the species are the spectator ions.

(ii) The balanced molecular equation will be,

The complete ionic equation in separated aqueous solution will be,

In this equation the species are the spectator ions.

Hence, the correct option is, (d)

(i)

(ii)

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

the answer is:  

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