A chemist prepares a solution of iron chloride by measuring out 0.10 g of FeCl2 into a 50. mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of anions in the chemist's solution.

The molarity of anions in the solution is 0.0316 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Given mass of iron (II) chloride = 0.10 g

Molar mass of iron (II) chloride = 126.75 g/mol

Volume of solution = 50 mL

Putting values in above equation, we get:

1 mole of iron (II) chloride produces 1 mole of ions and 2 moles of ions

So, concentration of chloride ions (anions) in the solution =

Hence, the molarity of anions in the solution is 0.0316 M

the answer is learned