The mass ratio of sodium to fluorine in sodium fluoride is 1.21: 1. a sample of sodium fluoride produced 32.5 \({\rm g}\) of sodium upon decomposition. how much fluorine (in grams) was formed? .

Let us assume the common ratio to be = x
Then
1.21x + x = 32.5
2.21x = 32.5
x = 32.5/2.21
   = 14.7
Amount of fluorine that was formed = 14.7 * 1 gm
                                                         = 14.7 gm
I hope that this answer has come to your help. 

Forgot the question hahaha

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