The temperature of a sample of gas in steel container at 30.3 Atm is
increased from -100.0 °C to 150 °C. What is the final pressure inside the
Given
Gas Law
Work
P1 =
1 P2 =
T1 =
Formula

74.09 atm

Explanation:

Using the gas laws ( Charles and Boyle's law). We have the formula ,

P1/T1 = P2/T2

Where P1 = 30.3atm

T1 = -100 degree Celsius

to kelvin = -100+ 273 = 173K

T2 = 150 degree Celsius

To Kelvin = 150 = 150+273 = 423K

Imputing values

P1/T1 = P2/T2

30.3/173 = P2/ 423

Cross multiply

173×P2 = 30.3 ×423

173P2 = 12816.9

Divide both sides by 173

P2 = 12816.9/173

P2 = 74.09 atm

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P2=74.086atm

Explanation:

Using the formula p1/t1=P2/t2

P1=30.3atm

P2=?

T1=-100°c to Kelvin=273-100=173k

T2=150°c to Kelvin=273+150=423k

30.3\173=x/423

Cross multiply

173x=423×30.3

173x=12816.9

Divide both sides by 173

X=74.086atm

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

answer; talc and gypsum;