What volume will o.128 g of propane, c3h8 occupy at a pressure golf 485 mm Hg and a temperature of 30.0 c

113 mL

Explanation:

Let's apply the Ideal Gases Law for this propose:

P . V = n . R .T → (n. R . T) / P = V

We need to convert the T° to Absolute T° and pressure from mmHg to atm

T° K = 30°C + 273 = 303K

485 mmHg . 1atm / 760 mmHg = 0.638 atm

Let's replace the information obtained:

V = (n . 0.082 . 303K) / 0.638 atm

n = number of moles → 0.128 g . 1mol / 44g = 0.00291 moles

V = (0.00291 moles . 0.082 . 303K) / 0.638 atm → 0.113 L

The value can be written as 113 mL

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying