Consider the following reaction: Pb(NO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaNO3(aq)If you react an excess of Pb(NO3)2with 26.3 g of NaCl, and you isolate 52.1 g of PbCl2, what is your percent yield?

Explanation:

Mᵣ:                          58.44      278.11

           Pb(NO₃)₂ + 2NaCl ⟶ PbCl₂ + 2NaNO₃

m/g:                         26.3

1. Moles of NaCl

(b) Moles of PbCl₂

(c) Theoretical yield of PbCl₂

(d) Percent yield

a galvanic cell( aka voltaic cell) and electrolytic cell

explanation:

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