What is the change in entropy when 0.7 m3 of CO2 and 0.3 m3 of N2, each at 1 bar and 25°C, blend to form a gas mixture at the same conditions? Assume ideal gases

Explanation:

The given data is as follows.

        P = 1 bar,     T = 298 K

For ;  

For ;    

Therefore, final volume will be as follows.

Hence,            

Formula for change in entropy is as follows.

          dS =

For ,  

or,                    

                       =        

                       = 234.89

                       = 83.77 J/K

For ,       nR =

                  =

                  = 100.67

                   = 121.20 J/K

Now, total change in the entropy is calculated as follows.

               dS =

                    = (83.77 + 121.20) J/K

                    = 204.97 J/K

Thus, we can conclude that the change in entropy is 204.97 J/K.

im pretty sure its b

i believe the answer is three water molecules