Chemistry, 05.03.2020 12:59 jennsou

Consider mixture C, which will cause the net reaction to proceed in reverse. Concentration (M)initial:change:equilibrium:[XY]0 .200+x0.200+x←net⇌[X]0.300−x0.300−x +[Y]0.300−x0.300−x The change in concentration, x, is positive for the reactants because they are produced and negative for the products because they are consumed.

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Answer from: kaaylon8285

This is an incomplete question, here is a complete question.

Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C, which will cause the net reaction to proceed in reverse.

The chemical reaction is:

$XY(g)\rightleftharpoons X(g)+Y(g)$

Concentration(M) [XY] [X] [Y]

(M)initial: 0.200 0.300 0.300

change: +x -x -x

equilibrium: 0.200+x 0.300-x 0.300-x

The change in concentration, x, is positive for the reactants because they are produced and negative for the products because they are consumed. Based on a Kc value of 0.140 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively?

Answer : The Equilibrium concentrations of XY, X, and Y is, 0.104 M, 0.204 M and 0.204 M respectively.

Explanation :

The chemical reaction is:

$XY(g)\rightleftharpoons X(g)+Y(g)$

initial: 0.200 0.300 0.300

change: +x -x -x

equilibrium: (0.200+x) (0.300-x) (0.300-x)

The equilibrium constant expression will be:

$K_c=\farc{[X][Y]}{[XY]}$

Now put all the given values in this expression, we get:

$0.140=\frac{(0.300-x)\times (0.300-x)}{(0.200+x)}$

By solving the term 'x', we get:

x = 0.0963 and x = 0.644

We are neglecting the value of x = 0.644 because the equilibrium concentration can not be more than initial concentration.

Thus, the value of x = 0.0963

Equilibrium concentrations of XY = 0.200+x = 0.200+0.0963 = 0.104 M

Equilibrium concentrations of X = 0.300-x = 0.300-0.0963 = 0.204 M

Answer from: Quest

14,16 18 reacts with group

Answer from: Quest

answer: e. sour taste

explanation: acids are those substances which dissociates in water to give $h^+$ ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

$hcl\rightarrow h^++cl^-$

bases are those substances which dissociates in water to give $oh^-$ ions or accepts $h^+$ ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.

$naoh\rightarrow na^++oh^-$

$nh_3+h^+\rightarrow nh_4^+$

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Consider mixture C, which will cause the net reaction to proceed in reverse. Concentration (M)initia...

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