Calculate the volume (in mL) of 6.25 x 10-4 M ferroin solution that needs to be added to a 10.0 mL volumetric flask and diluted with deionized (DI) water in order to prepare a calibration standard solution with a concentration of 2.50 x 10-5 M ferroin. As part of your preparation for performing this experiment, repeat this calculation for each of the calibration standards you will need to prepare and record the information in your lab notebook so that you have it ready during the lab session. Group of answer choices 0.200 mL 0.400 mL 0.600 mL 0.800 mL none of the above

The volume of solution required is 0.400 mL.

In this case, we have to use the dilution formula;

C1V1 = C2 V2

In this case;

C1 =  6.25 x 10-4 M

V1 = ?

C2 = 2.50 x 10-5 M

V2 = 10.0 mL

Making V1 the subject of the formula;

V1 = C2V2/C1

V1 = 2.50 x 10-5 M x 10.0 mL/6.25 x 10-4 M

V1 = 0.400 mL

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The volume V2 is 0.400 ml

Explanation:

The dilution equation is the product of initial values of molarity and volume which is equal to the product of final values of molarity and volume.

The dilution equation is given by

                          M1 V1 = M2 V2

where,

M represents the molarity of the solution  

V represents the volume of the solution

M1 and V1 are the initial values  of the solution

M2 and V2 are the final values of the solution

                            M1 V1 = M2 V2

               (2.5 ) 10 = (6.25 ) V2  

                                    V2 = 2.5 / (6.25 )  

                                    V2 = 0.4

    The volume V2 is 0.400 ml

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the ratio of the conjugate base to the acid required to attain the desired ph.