A 2.00-L glass soda bottle filled only with air is tightly capped at 25°C and 728.0 mmHg. If the bottle is placed in water at 65°C, what is the pressure in the bottle?

The pressure in the bottle is 826 mmHg

Explanation:

In this case it is assumed that the volume of the soda bottle does not change, so it remains constant with a value of 2.00 L. Then it is possible to apply the Gay Lussac law.

This law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature decreases, gas pressure decreases. That is, the gas pressure is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

Where P = pressure, T = temperature and K = Constant

Having a gas that is at a pressure P1 and a temperature T1, as the temperature varies to a new T2 value, then the pressure will change to P2. It is then fulfilled:

Remember that the temperature must be in degrees Kelvin (° K) and that 0 ° C is 273.15 ° K

In this case you know:

Replacing:

Resolving you get:

P2=825.67 mmHg≅826 mmHg

The pressure in the bottle is 826 mmHg

0.88m hope i am correct : )