A flask containing 155cm^3 of hydrogen was collected under a pressure of 22.5kPa. What pressure would have been required in order for the volume of the gas to have been 90.0 cm^3 at constant temperature ?

38.75KPa

Explanation:

The following were obtained from the question:

V1 = 155cm^3

P1 = 22.5kPa

V2 = 90cm^3

P2 =?

The new pressure can obtain by doing the following:

P1V1 = P2V2

22.5 x 155 = P2 x 90

Divide both side by 90

P2 = (22.5 x 155) /90

P2 = 38.75KPa

b) nuclear ive learned that in a pedtrodic table