Write the balanced chemical equation for the combustion of ethane, , and answer these questions. (Use the lowest possible coefficients. Omit states of matter.) How many molecules of oxygen would combine with 16 molecules of ethane in this reaction

1. 2C2H6 + 7O2 —> 4CO2 + 6H2O

2. 56moles of O2

Explanation:

Ethane undergo Combustion to produce CO2 and H20 according the equation below:

C2H6 + O2 —> CO2 + H2O

Let us balance the equation. There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balanced by putting 3 in front of H2O as shown below:

C2H6 + O2 —> CO2 + 3H2O

There are 2 atoms of C on left and 1atom on the right. It can be balanced by putting 2 in front of CO2 as shown below:

C2H6 + O2 —> 2CO2 + 3H2O

There are a total of 7 atoms of O on the right and 2 atoms on the left. It can be balanced by putting 7/2 in front of O2 as shown below:

C2H6 + 7/2O2 —> 2CO2 + 3H2O

Now we multiply through by 2 to remove the fraction as shown below

2C2H6 + 7O2 —> 4CO2 + 6H2O

Now the equation is balanced

2. 2C2H6 + 7O2 —> 4CO2 + 6H2O

From the equation above,

2 moles of ethane(C2H6) combined with 7moles of O2.

Therefore, 16moles of ethane(C2H6) will combine with = (16x7)/2 = 56moles of O2

i think it's letter a.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally