Given the value of the equilibrium constant (Kc) for the equation (a), calculate the equilibrium constant for equation (b)

(a) O2 (g)>2/3O3(g) Kc=5.77x10^-9

(b) 3O2 (g)>2O3(g) Kc=?

The value of equilibrium constant for new reaction is

Explanation:

The given chemical equation follows:

The equilibrium constant for the above equation is

We need to calculate the equilibrium constant for the equation of 3 times of the above chemical equation, which is:

The equilibrium constant for this reaction will be the cube of the initial reaction.

If the equation is multiplied by a factor of '3', the equilibrium constant of the new reaction will be the cube of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

Hence, the value of equilibrium constant for new reaction is

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explanation:

because it is

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