A solution of hydrochloric acid of unknown concentration was titrated with .21 M NaOH. if a 75 ml sample of the HCl solution required exactly 13ml of the NaOH solution to reach the equivalence point, what was the ph of the HCl solution

pH of HCl solution is 1.44

Explanation:

NaOH is a monoprotic base and HCl is a monobasic acid.

Neutralization reaction:

According to balanced reaction, 1 mol of NaOH neutralizes 1 mol of HCl.

Number of moles of NaOH in 13 mL of 0.21 M NaOH

=

let's assume concentration of HCl is C (M)

Then, number of moles of HCl in 75 mL of C (M) HCl solution

=

So, we can write,

or,

1 mol of HCl contains 1 mol of

So, concentration of in 0.0364 M HCl,

Hence,

imma come back to you hold on

1.solid

2.carbon dioxide

3.helium