Determine the volume of hexane that contains 5.33 × 1022 molecules of hexane. The density of hexane is 0.6548 g/mL and its molar mass is 86.17 g/mol. Determine the volume of hexane that contains 5.33 × 1022 molecules of hexane. The density of hexane is 0.6548 g/mL and its molar mass is 86.17 g/mol. 13.5 mL 11.6 mL 7.40 mL 8.59 mL 12.4 mL

11.6 mL is the volume for 5.33 × 10²² molecules of hexane

Explanation:

We analyse data:

5.33 × 10²² molecules of hexane

0.6548 g/mL

86.17 g/mol

First of all, we determine the moles of hexane that contain 5.33 × 10²² molecules

6.02×10²³ molecules are contained in 1 mol

5.33 × 10²² molecules must be contained in (5.33 × 10²² . 1) / NA = 0.088 moles

Now we convert the moles to mass → 0.088 mol . 86.17 g/m = 7.63 g

Finally we apply density to determine the volume

Density = mass / volume → Volume = Mass / Density

Volume = 7.63 g / 0.6548 g/mL = 11.6 mL

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the answer is 303.15 or 303