The analysis of an organic compound showed that it contained 0.630 mol of C, 0.0300 mol of H, 0.420 mol of O, and 0.210 mol of N. How many nitrogen atoms are there in the empirical formula for this compound?

The empirical formula is C21HO14N7

Explanation:

Step 1: Data given

Number of moles of C = 0.630 moles

Number of moles H = 0.0300 moles

Number of moles O = 0.420 moles

Number of moles N = 0.210 moles

Step 2: Calculate the mol ratio

We divide by the smallest amount of moles

C: 0.630 moles / 0.0300 moles = 21

H: 0.0300 moles / 0.0300 moles =  1

O: 0.420 moles / 0.0300 moles = 14

N: 0.210 moles / 0.0300 moles =  7

The empirical formula is C21HO14N7

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.