The student determines the molar mass of the gas to be 64 g mol-1. write the expression (set-up) for calculating the percent error in the experimental value, assuming that the unknown gas is butane (molar mass 58 g mol-1). calculations are not required

Percentage error = x 100%

Explanation:

In order to calculate the percentage error in the student's calculation, the following formula will be used:

Percentage error = x 100%

experimental molar mass = 64 g/mol

theoretical molar mass = 58 g/mol

Hence, the expression becomes:

Percentage error = x 100%

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answersilicon (si); oxygen (o);