At a certain temperature, Kp for the reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g) is 0.00029. Calculate the value of Kp for the reaction, BrCl(g) <=> 1/2 Cl2(g) + 1/2 Br2(g)

Kp = 59

Explanation:

For the reaction:

Cl₂(g) + Br₂(g) ⇄ 2BrCl(g) Kp = 0,00029

The k of the reciprocal reaction is:

2BrCl(g) ⇄ Cl₂(g) + Br₂(g) Kp = 1/0,00029 = 3448

As the kp of the reaction that we need to calculate is the half of the last reaction, that is:

BrCl(g) ⇄ ¹/₂Cl₂(g) + ¹/₂Br₂(g) Kp is √3448 = 59

I hope it helps!