Wastewater discharged into a stream by a sugar refinery contains 1.70 g of sucrose (C12H22O11) per liter. A government-industry project is designed to test the feasibility of removing the sugar by reverse osmosis. What pressure must be applied to the apparatus at 20.°C to produce pure water?

A pressure value more than 0.012 atm must be applied to the apparatus at 20.0°C to produce pure water.

Explanation:

When pressure more than the value of osmotic pressure of the solution is applied to the solution then water will move out from the solution which is termed as reverse osmosis.

Given that 1.70 grams of sucrose was present in 1 L of solution.

Moles of sucrose present in 1 liter of solution  =

C = 0.004971 mol/L

Temperature of the solution = T = 20.0°C = 20.0+273 K = 293 K

Osmotic pressure of soluion =

A pressure value more than 0.012 atm must be applied to the apparatus at 20.0°C to produce pure water.

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).

m=9

step-by-step explanation: