A sample of 3.785 g of a compound is analyzed, and found to contain 1.302 g Fe and 2.483 g Cl. Another sample of the compound is found to contain 2.329 g of Cl. How many grams of Fe will it contain

1.221g

Explanation:

First Sample

Ratio of  Fe and Cl is given as;

Mass of Fe: Mass of Cl

1.302g : 2.483g

Second Sample;

Mass of Fe: Mass of Cl

xg : 2.329g

The ratio between both elements is constant in both samples, so we have;

Ratio of first sample = Ratio of second sample

1.302g : 2.483g = xg : 2.329g

1.302 / 2.483 = x / 2.329

x = (2.329 * 1.302) / 2.483

x = 1.221g

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.