Determine the value of the equilibrium constant, Kgoal, for the reaction N2(g)+O2(g)+H2(g)⇌12N2H4(g)+NO2(g), Kgoal=? by making use of the following information: 1. N2(g)+O2(g)⇌2NO(g), K1 = 4.10×10−31 2. N2(g)+2H2(g)⇌N2H4(g), K2 = 7.40×10−26 3. 2NO(g)+O2(g)⇌2NO2(g), K3 = 6.00×10−13 Express your answer numerically.

Answer : The value of the equilibrium constant is,

Explanation :

The given main reaction is:

The intermediate reactions are:

;  

;  

;  

Now we are adding all the equation, we get:

          ...........(1)

The equilibrium constant expression will be:

Now we are dividing equation 1 by 2, we get:

          ...........(1)

The equilibrium constant expression will be:

Now put all the given values in this expression, we get:

Thus, the value of the equilibrium constant is,

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"