The specific heat capacity of gold is 0.128 J/g ºC. How much heat would be needed to warm 250.0 grams of gold from 25.0 ºC to 100.0 ºC? A. 2.4 x10-3J B. -2.40 x 103J C. 2.40 x 103J D. -2.40 x 10-3J

C. 2.40 × 10³ J  

Explanation:

The formula for the amount of heat (q) absorbed is

q = mCΔT

1. Calculate ΔT

ΔT = 100.0 °C - 25.0 °C = 75.0 °C

2. Calculate q

q₂ = mCΔT = 250.0 g × 0.128 J·°C⁻¹g⁻¹ × 75.0 °C = 2.40 × 10³ J

the old alchemists made significant contributions to science even though there starting premises were off a bit. their conclusions after failure would steer them into better directions for investigation. science is no more than close observation and the initial mistakes result in rethinking and retrying experiments.

1.solid

2.carbon dioxide

3.helium