What volume (in L) of a 6.84 M.
sodium bromide (NaBr) solution
would be needed to make 588 mL of
a 1.84 M solution by dilution?

0.158L

Explanation:

From the question, we obtained the following information:

C1 = 6.84 M

V1 =?

C2 = 1.84 M

V2 = 588 mL = 588/1000 = 0.588L

Using the dilution formula C1V1 = C2V2. The original volume can calculated for as follows:

C1V1 = C2V2

6.84 x V1 = 1.84 x 0.588

Divide both side by 6.84

V1 =(1.84 x 0.588) / 6.84

V1 = 0.158L

a:

by the combination of an unlimited number of elements