Please help!

Consider the reaction of hydrogen and oxygen to form water as follows:

2 H2 (g) + O2 (g) --> 2 H2O (l)

if 10.5 g of hydrogen are placed in a reaction vessel, how many grams of oxygen are required to fully react with the hydrogen to make water? Numerical answers only; do not include units in your answer!

84 grams

Explanation:

10.5 G of H2 in moles = (10.5/2)mol = 5.25 mol

H2 : O2

2 : 1

Therefore

When H2 =5.25mol

O2 = 5.25/2 =2.625mol

2.625mol of O2 in grams = 2.625mol * 32 gmol-1

=84 g

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step-by-step explanation: