1. Given the following equation:
2C4H10 +13O2 --->8CO2 +10H2O
Show what the following molar ratios should be.
a. C4H10 / O2 2:13 (example) b. O2 / CO2
c. O2 / H2O
d. C4H10 / CO2
e. C4H10 / H2O

The molar ratio of O2 / CO2 is 13:8, O2/H2O is 13:10, C4H10 / CO2 is 1:4 and C4H10 / H2O is 1:5.

The mole concept is the concept of how many moles of a reactant reacts with how many moles of the reagent to produce how many moles of product. It gives us the stoichiometric ratio of the reactants with the products.

In the reaction we can see that 2 moles of butane reacts with 13 moles of oxygen to produce 8 moles of carbon dioxide and 10 moles of water.  So the molar ratio of O2 / CO2 is 13:8, O2/H2O is 13:10, C4H10 / CO2 is 1:4 and C4H10 / H2O is 1:5.

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2