Aqueous potassium phosphate reacts with aqueous aluminum chloride to form aqueous potassium chloride and solid aluminum phosphate. Write the balanced chemical equation for the reaction. Include physical states.

The balanced equation of the reaction between aqueous aluminum chloride and potassium phosphate to form aqueous potassium chloride and solid aluminum phosphate would be:

+   --->   +  

Aqueous potassium phosphate has the formula

Aqueous aluminum chloride has the formula

Aqueous potassium chloride has the formula

Solid aluminum phosphate has the formula

The balanced equation for the reaction can, thus, be written as:

  +   --->   +  

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Al^3+(aq) + PO4^3-(aq) → AlPO4(s)

Explanation:

Step 1: Data given

potassium phosphate = K3PO4

aluminum chloride = AlCl3

potassium chloride = KCl

aluminum phosphate = AlPO4

Step 2: The unbalanced equation

K3PO4(aq) + AlCl3(aq) → KCl (aq)+ AlPO4(s)

On the left side we have 3x K (in K3PO4), on the right side we have 1x K (in KCl). To balance the amount of K on both sides, we have to multiply KCl (on the right side ) by 3. Now the equation is balanced.

K3PO4(aq) + AlCl3(aq) → 3KCl(aq)+ AlPO4(s)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

Al^3+(aq) + PO4^3-(aq) → AlPO4(s)