For the chemical reaction 2 HBr ( aq ) + Ba ( OH ) 2 ( aq ) ⟶ 2 H 2 O ( l ) + BaBr 2 ( aq ) 2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2( aq) write the net ionic equation, including the phases.

The net ionic equation, including the phases, for the chemical reaction is,

2H⁺(aq) + 2OH⁻(aq) ⟶ 2H₂O(l)

From the question,

We are to write the net ionic equation for the given chemical reaction.

The given balanced chemical equation for the reaction is

2HBr(aq) + Ba(OH)₂(aq) ⟶ 2H₂O(l) + BaBr₂(aq)

Now, we will write the ionic equation for the reaction

The ionic equation for the reaction is

2H⁺(aq) + 2Br⁻(aq) + Ba²⁺(aq) + 2OH⁻(aq) ⟶ 2H₂O(l) + Ba²⁺(aq) + 2Br⁻(aq)

Now, cancel out the spectator ions,  Ba²⁺ and Br⁻, to give the net ionic equation.

The net ionic equation is

2H⁺(aq)  + 2OH⁻(aq) ⟶ 2H₂O(l)

Hence, the net ionic equation, including the phases, for the chemical reaction is,

2H⁺(aq) + 2OH⁻(aq) ⟶ 2H₂O(l)

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2H+ (aq) + 2OH-(aq)→ 2H2O (l)

Explanation:

Step 1: the balanced equation

2HBr(aq) + Ba(OH)2(aq) ⟶ 2H2O(l)+BaBr2(aq)

Step 2: The net ionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side (Ba^2+ and Br-), look like this:

2H+ (aq) + 2OH-(aq)→ 2H2O (l)

there are two significant figures.