Nitrosyl bromide decomposes according to the chemical equation below. 2NOBr(g) ↔ 2NO(g) + Br2(g) When 0.260 atm of NOBr is sealed in a flask and allowed to reach equilibrium, 22% of the NOBr decomposes. What is the equilibrium constant, Kp, for the reaction?

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0.260 atm of NOBr is sealed in a flask and allowed to reach equilibrium, 22% of the NOBr decomposes

2NOBr       ↔       2NO(g) + Br_2

0.26                       0                0

-2X                        +2X             X

At equilibrium,

Therefore,

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Equilibrium constant, Kp, for the reaction is 0.00227

Explanation:

We are given:

The chemical reaction for the decomposition follows the equation:

At t = 0          0.260           0     0    

At      0.260-2x          2x       x

The expression for for the given reaction follows:

We are given:

Putting values in above equation, we get:

Thus equilibrium constant, Kp, for the reaction is 0.00227

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