An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standard enthalpy of combustion of the fuel is − 26.5kJ/g. Calculate the maximum power (in units of kilowatts) that can be produced by this spacecraft. 1kW = 1kJ/s?

Explanation:

First, we will calculate fuel consumption is as follows.

           = 4526 g/s

Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

                    =

                    = kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is kW.

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