At 25°C, gaseous decomposes to and to the extent that 10.3% of the original (by moles) has decomposed to reach equilibrium. The total pressure (at equilibrium) is 1.30 atm. Calculate the value of for this system. =

The question is incomplete, complete question is :

At 25°C, gaseous decomposes to and to the extent that 10.3% of the original

The value of the of the reaction is 0.0139.

Explanation:

The total pressure at equilibrium = P = 1.30 atm.

Initially

1 mol              0       0

At equilibrium:

(1 - 0.103)mol     0.103 mol      0.103 mol

Total moles at equilibrium,n = (1-0.103)mol+  0.103 mol + 0.103 mol

n = 1.103 moles

At equilibrium ,mole fraction of

Partial pressure of f equilibrium ;

(Dalton's law of partial pressure)

At equilibrium ,mole fraction of

Partial pressure of f equilibrium ;

(Dalton's law of partial pressure)

At equilibrium ,mole fraction of

Partial pressure of f equilibrium ;

(Dalton's law of partial pressure)

The value of the of the reaction will be;

here are some of the ways in which chemical and nuclear reactions differ.

explanation: