What is the theoretical yield of fe2(so4)3 if 20.00 g of fepo4 reacts with an excess of na2so4?

The balanced chemical reaction is:

 FePO4 + Na2SO4 = Fe2(SO4)3 + Na3PO4

We are given the amount of FePO4  is given to be used in this reaction. This will be the starting point for the calculations.

20.0 g FePO4  ( 1 mol FePO4/ 150.82 g FePO4 ) ( 1 mol Fe2(SO4)3 / 1 mol FePO4) ( 399.88 g Fe2(SO4)3/ 1 mol Fe2(SO4)3) = 53.0274 g Fe2(SO4)3

A) the enthralling of formation for pure element in its standard state is always positivehope this : )