At 473 K, for the elementary reaction 2NOCl(g)k1⇌k−12NO(g)+Cl2(g) k1=7.8×10−2L/mols and k−1=4.7×102L2/mol2s A sample of NACl is placed in a container and heated to 473 K. When the system comes to equilibrium, [NOCl] is found to be 0.58 mol/L .

Part a)

Part b)

Explanation:

The complete question is:

At 473 K, for the elementary reaction 2NOCl(g) ⇌2NO(g)+Cl₂(g)

k₁ = 7.8×10⁻² L/mol.s and k⁻¹ =4.7×10²L²/mol².s .

A sample of NOCl is placed in a container and heated to 473 K. When the system comes to equilibrium, [NOCl] is found to be 0.58 mol/L.

Part a) Calculate the concentration of NO

Part b) Calculate the concentration of Cl₂

1. Calculate the equilibrium constant.

k₁  is the rate constant of the forward reaction and k⁻¹  is the rate constant of the reverse reaction.

The equilibrium constant is the quotient of the rate constant for the forward reaction and the rate constant of the reverse reaction:

2. Build the ICE (Initial, Change, Equilibrium) table

                       2NOCl(g)       ⇌           2NO(g)    +       Cl₂(g)

Initial                     A                                   0                     0

Change               -2x                               +2x                   +x

Equilibrium        A - 2x                             2x                     x

                          A - 2x = 0.58 mol/L

3. Write the equilibrium constant equation

4. Solve the equation

5. Concentrations

Part a)

Part b)

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.