Complete the equation for the dissociation of CdCl 2 ( aq ) . CdCl2(aq). Omit water from the equation because it is understood to be present. equation: CdCl 2 ( aq ) ⟶

The answer to your question is         CdCl₂  ⇒   Cd⁺²  +  2Cl⁻¹      

Explanation:

Data

Reactant = CdCl₂ (aq)

Process

1.- Determine the products of this reaction

The products will be the elements that form part of this compound (Cadmium and chlorine).

2.- Write the dissociation reaction

                      CdCl₂  ⇒   Cd⁺²  +  Cl⁻¹

3.- Balance the reaction

                      CdCl₂  ⇒   Cd⁺²  +  Cl⁻¹      

            Reactants    Elements     Products

                    1                 Cd                 1

                    2                 Cl                  1

The reaction is unbalanced

                     CdCl₂  ⇒   Cd⁺²  +  2Cl⁻¹      

            Reactants    Elements     Products

                    1                 Cd                 1

                    2                 Cl                  2

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o