For the reaction, A(g) + B(g) => AB(g), the rate is 0.385 mol/L. s when the initial concentrations of both A and B are 2.00 mol/L. If the reaction is second order in A and first order in B, what is the rate when the initial concentration of A = 1.48 mol/L and that of B = 1.32 mol/L. Give your answer to 2 decimal places

Answer : The rate for a reaction will be

Explanation :

The balanced equations will be:

In this reaction, and are the reactants.

The rate law expression for the reaction is:

or,

Now, calculating the value of 'k' by using any expression.

Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.

Therefore, the rate for a reaction will be