A student adds 10.00 mL of a 2.0 M nitric acid solution to a 100.00 mL volumetric flask. Next, 50.00 mL of a 0.00500 M solution of KSCN is added by pipet. Deionized water is added to the flask to dilute the solution to the 100.00 mL mark. What is the concentration of the new solution?

0,20M of nitric acid

0,00250M of KSCN

Explanation:

For nitric acid, the dilution is from 10,00mL to 100,00mL. That is a 1/10 dilution. As the initial concentration of nitric acid is 2,0M, the new concentration is: 2,0M× (1/10) = 0,20M of nitric acid

For KSCN the dilution is from 50,00mL to 100,00mL, that is a dilution 1/2. Thus, the new concentration of KSCN is:

0,00500M × (1/2) = 0,00250M of KSCN

I hope it helps!

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.