Calculate the percent ionization of propionic acid (C2H5COOH) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook).

Part A. 0.270 M

Part B. 7.84×10-2 M

Part C. 1.97×10-2 M

a) = 0.704%

b) = 1.30%

c) = 2.60%

Explanation:

Given that:

=

For Part A; where Concentration of A = 0.270 M

Percentage Ionization(∝)  

percentage% (∝) =

= 0.704%

For Part B; where Concentration of B = M

percentage% (∝) = 0.0130 × 100%

= 1.30%

For Part C; where Concentration of C=

percentage% (∝) = 0.02608  × 100%

= 2.60%

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3