The complete combustion of propane (C3H8) in the presence of oxygen yields CO2 and H2O:
C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g)
a. Calcluate the volume of carbon dioixde ( at s. t.p.) that would be produced by the
combustion of 27.5 g of C3H8 burns in the presence of 45.0 L of O2.

Explanation:

We are given the amounts of two reactants and asked to determine the amount of product.

This is a limiting reactant problem.

1. Assemble the information

We will need a balanced chemical equation with molar masses and volumes, so, let's gather all the information in one place.

MV/L:                    22.71    22.71

Mᵣ:             44.10

                  C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

m/g:            27.5

V/L:                        45.0

2. Calculate the moles of each reactant

(a) Propane

(b) Oxygen

The volume of 1 mol of a gas at STP (0 °C and 1 bar) is 22.71 L

3. Calculate the moles of CO₂ from each reactant

4. Calculate the volume of CO₂

answer

the ions in solute supperate from eachouthere

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.