Chemistry, 25.02.2020 05:57 MeowieMeowMeow3891
If the rate of disappearance of N2O5 is equal to 1.40 mol/min at a particular moment, what is the rate of appearance of NO2 at that moment? Enter your answer with 2 decimal places and no units.
Answers: 3
at that moment.
![R=\frac{-1}{2}\frac{d[N_2O_5]}{dt}=\frac{1}{4}\frac{d[NO_2]}{dt}=\frac{1}{1}\frac{d[O_2]}{dt}](/tpl/images/0522/9642/6c262.png)
is ![=-\frac{d[N_2O_5]}{dt}= 1.40 mol/min](/tpl/images/0522/9642/01ec3.png)
![R=\frac{-1}{2}\frac{d[NO_2]}{dt}](/tpl/images/0522/9642/10b2e.png)
![=\frac{1}{4}\frac{d[NO_2]}{dt}:](/tpl/images/0522/9642/470ff.png)
![R=\frac{1}{4}\frac{d[NO_2]}{dt}](/tpl/images/0522/9642/778a0.png)
![\frac{d[NO_2]}{dt}=4\times 0.70 mol/min=2.8 mol/min](/tpl/images/0522/9642/c6544.png)
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If the rate of disappearance of N2O5 is equal to 1.40 mol/min at a particular moment, what is the ra...
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