1) Of the following transitions in the Bohr hydrogen atom, the transition results in the emission of the highest-energy photon. A) n = 1 → n = 6 B) n = 6 → n = 1 C) n = 6 → n = 3 D) n = 3 → n = 6 E) n = 1 → n = 4

B. n = 6 → n = 1

Explanation:

B: n=6, n=1 is highest-energy photon. Emission is going from a higher energy level down to a lower energy level, so that will rule out a,d,e. So between b and c, it will be b because if you study the n=1 energy level you will see that it is the ground state energy level, which means that energy is the greatest in this energy level.

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