A chemist adds of a M sodium nitrate solution to a reaction flask. Calculate the mass in grams of sodium nitrate the chemist has added to the flask. Round your answer to significant digits.

The question is incomplete. The complete question is:

A chemist adds 390.0 mL of a 2.1M sodium nitrate solution to a reaction flask. Calculate the mass in grams of sodium nitrate the chemist has added to the flask. Round your answer to 2 significant digits.

70 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = moles of solute

= volume of solution in ml

moles of  =

Now put all the given values in the formula of molality, we get

Therefore, the mass in grams of sodium nitrate the chemist has added to the flask is 70 grams

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.