Nitroglycerine decomposes violently according to the chemical equation below. What mass of carbon dioxide gas is produced from the decomposition of 13.3 g C3H5(NO3)3? 4 C3H5(NO3)3() → 12 CO2(g) + 6 N2(g) +10 H2O(g) + O2(g)

Answer : The mass of  produced is, 7.74 grams

Solution : Given,

Mass of = 13.3 g

Molar mass of = 227 g/mole

Molar mass of = 44 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of

The balanced chemical reaction is,

From the reaction, we conclude that

As, 4 mole of react to give 12 mole of

So, 0.0586 moles of react to give moles of

Now we have to calculate the mass of

Thus, the mass of  produced is, 7.74 grams

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied