Balance the equation NH4OH + H3PO4

What Are the products of NH4OH + H3PO4

3NH₄OH  +  H₃PO₄  → (NH₄)₃PO₄  +  3H₂O

Products are water and  ammonium phosphate

Explanation:

This is a neutralization between a weak base and a weak acid where the products are water and the correspondent salt.

Base:  NH₄OH  →  NH₄⁺  +  OH⁻

Acid :  H₃PO₄  →  3H⁺  +  PO₄⁻³

H⁺ bonds to OH⁻ to make H₂O → As we have 3 protons, we can make 3 moles of water, so there are needed 3 OH⁻.

Phosphate has -3 as oxidation state, then it needs 3 ammonium to form the salt.

The balanced equation is:

3NH₄OH  +  H₃PO₄  → (NH₄)₃PO₄  +  3H₂O

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%