Chemistry, 08.10.2019 21:30 ny01282005
If the [h+] changed from [1 x 10-7] to [1 x 10-4], what is the new [oh-]?
Answers: 3
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ions = ![[H^+]=1\times 10^{-7} M](/tpl/images/0301/4514/a19c7.png)
![[H^+]'=1\times 10^{-4} M](/tpl/images/0301/4514/ab1c9.png)
![pH=-\log[H^+]'=-\log[1\times 10^{-4}]=4](/tpl/images/0301/4514/8caa6.png)
![pOH=-\log[OH^-]](/tpl/images/0301/4514/fe336.png)
![10=-\log[OH^-]](/tpl/images/0301/4514/01106.png)
![[OH^-]=1\times 10^{-10} M](/tpl/images/0301/4514/72671.png)
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If the [h+] changed from [1 x 10-7] to [1 x 10-4], what is the new [oh-]?...
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