How many formula units of sodium nitrate will react with 25.0g of calcium carbonate to produce sodium carbonate and calcium nitrate

Complete Question:

How many formula units of sodium nitrate will react with 25.0 g of calcium carbonate to  product sodium carbonate and calcium nitrate according to the following reactions?  

2 Na(NO3) + Ca(CO3) → Na2(CO3) + Ca(NO3)2

formula units of sodium nitrate will react with 25.0 g of calcium carbonate to produce sodium carbonate and calcium nitrate according to the equation.

Explanation:

Given chemical equation:

Given mass of calcium carbonate = 25 g

We need to determine the number of formula units of sodium nitrate that will react with 25 g of calcium carbonate.

Step 1: To calculate the number of moles of Calcium carbonate

Number of mole is the ratio of mass to the molar mass, given as

molar mass of calcium carbonate = 100.0869 g / mol

Step 2: Moles of Sodium nitrate that reacted

From the equation, 2 moles of NaNO₃ reacts with 1 mole of CaCO₃

Thus, the mole ratio of NaNO₃ to CaCO₃ is 2 : 1

Therefore; Number of moles of NaNO₃ = Moles of CaCO₃ × 2

                  Number of moles of NaNO₃ = 0.25 × 2 = 0.5 moles

Step 3: Calculate formula units of NaNO₃

We need to know that 1 mole of a compound contains formula units equivalent to the Avogadro's constant.

     1 mole of a compound contains formula units

Therefore; 0.5 moles of NaNO₃ will have;

             = 0.5 × formula units

            = 3.011 formula units

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