If 125 mL of a 1.1 M glucose solution is diluted to 500.0 mL , what is the molarity of the diluted solution? Express your answer using two significant figures.

0.28M

Explanation:

From the question given, we obtained the following information:

C1 = 1.1 M

V1 = 125mL

V2 = 500mL

C2 =?

Using the dilution formula C1V1 = C2V2, we can easily find the molarity of the diluted solution as follows:

C1V1 = C2V2

1.1 x 125 = C2 x 500

Divide both side by 500

C2 = (1.1 x 125)/500 =

C2 = 0.28M

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.