A pharmacist has a 12% solution of boric acid and a 20% solution of boric acid. How much of each must he use to make 80 grams of a 15% boric acid solution

Explanation:

Call x the amount of 12% boric acid solution to be used.

Since he wants to make 80 grams of solution, the amount of 20% boric acid solution to be used is 80 - x.

The final solution is 15% concentrated.

Now you have can write your equation:

Solve:

That is 50 grams of the 12% solution of boric acid.

Calculate the amount of the 20% solution of boric acid:

That is 30 grams.

Then, he must use 50g of the 12% solution and 30 g of the 20% solution.

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.