What is the empirical formula of a compound that is 14 g calcium, 11 g oxygen, and 0.7 g hydrogen?
a. ca2oh2
b. ca(oh)2
c. cao2h
d. caoh

We are given with the mass of the elements. Taking a 100-gram basis, we convert the mass of the reactants to moles. Calcium is equal to 0.35 moles , oxygen is equal to 0.6875 and hydrogen is equal to 0.7 moles. We divide each number to the less amount. Hence Ca is 1, O is 1.96 and H is 2. Answer is B. Ca(OH)2, calcium hydroxide.

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