One of the intermediates in the synthesis of glycine from ammonia, carbon dioxide, and methane is aminoacetonitrile, C2H4N2.
How much C2H4N2 could be expected from the reaction of 14.9 g CO2, 2.11 g NH3, and 1.75 g CH4?

Explanation:

You must start by stating the chemical equation for the reaction of ammonia, carbon dioxide, and methane to produce aminoaceto nitrile.

1. Word equation:

Ammonia + Carbon dioxide + Methane → Aminoacetonitrile + Water

2. Balanced chemical equation:

3. Convert the mass of each reactant into number of moles:

Formula:

2.11g NH₃

14.9g CO₂

1.75g CH₄

4. Theoretical mol ratio

From the balanced chemical equation, using the coefficientes:

5. Limiting reagent

The available amounts of the reactants are:

Fom the theoretical mole ration, to react with 0.124 mol of NH₃ you would need:

Since there are 0.339 moles available, this is in excess.

Since there are 0.109 moles available, this is in excess too.

Hence, the limiting reagent is NH₃.

6. Yield

Use the theoretical ratio:

Convert to grams:

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."